Integrand size = 24, antiderivative size = 35 \[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{5/2}} \, dx=-\frac {\sqrt [4]{3} \left (4-e^2 x^2\right )^{5/4}}{5 e (2+e x)^{5/2}} \]
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Time = 0.01 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.042, Rules used = {665} \[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{5/2}} \, dx=-\frac {\sqrt [4]{3} \left (4-e^2 x^2\right )^{5/4}}{5 e (e x+2)^{5/2}} \]
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Rule 665
Rubi steps \begin{align*} \text {integral}& = -\frac {\sqrt [4]{3} \left (4-e^2 x^2\right )^{5/4}}{5 e (2+e x)^{5/2}} \\ \end{align*}
Time = 0.32 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.00 \[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{5/2}} \, dx=-\frac {\sqrt [4]{3} \left (4-e^2 x^2\right )^{5/4}}{5 e (2+e x)^{5/2}} \]
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Time = 2.27 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.86
method | result | size |
gosper | \(\frac {\left (e x -2\right ) \left (-3 x^{2} e^{2}+12\right )^{\frac {1}{4}}}{5 \left (e x +2\right )^{\frac {3}{2}} e}\) | \(30\) |
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none
Time = 0.34 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.29 \[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{5/2}} \, dx=\frac {{\left (-3 \, e^{2} x^{2} + 12\right )}^{\frac {1}{4}} \sqrt {e x + 2} {\left (e x - 2\right )}}{5 \, {\left (e^{3} x^{2} + 4 \, e^{2} x + 4 \, e\right )}} \]
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\[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{5/2}} \, dx=\sqrt [4]{3} \int \frac {\sqrt [4]{- e^{2} x^{2} + 4}}{e^{2} x^{2} \sqrt {e x + 2} + 4 e x \sqrt {e x + 2} + 4 \sqrt {e x + 2}}\, dx \]
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\[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{5/2}} \, dx=\int { \frac {{\left (-3 \, e^{2} x^{2} + 12\right )}^{\frac {1}{4}}}{{\left (e x + 2\right )}^{\frac {5}{2}}} \,d x } \]
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none
Time = 0.29 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.60 \[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{5/2}} \, dx=-\frac {3^{\frac {1}{4}} {\left (\frac {4}{e x + 2} - 1\right )}^{\frac {5}{4}}}{5 \, e} \]
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Time = 10.51 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.40 \[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{5/2}} \, dx=\frac {\left (\frac {x}{5\,e}-\frac {2}{5\,e^2}\right )\,{\left (12-3\,e^2\,x^2\right )}^{1/4}}{\frac {2\,\sqrt {e\,x+2}}{e}+x\,\sqrt {e\,x+2}} \]
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